300 g of water at 25ºC is added to 100 g of ice at 0ºC. Find the final temperature of the mixture.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(0ºC)
Sol. Heat liberated when 300 g water at 25ºC goes to water at 0ºC:
Q = ms Δθ
= (300) (1) (25)
= 7500 cal
From Q = mL, this much heat can melt mass of ice given by
m = 
= 
= 93.75 g
i.e., whole ice will not melt.
Hence, the mixture will be at 0ºC
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